Why the size of s2 array is 8 ????

Question

int x, y;
char s1[] = "Sololearn";
char s2[] = {'S', 'o', 'l', 'o', 'q', 'u', 'i', 'z'};
x =sizeof(s1);
y = sizeof(s2);
printf("%d, %d",x, y);

O/P :- 10,8

Answer 1

if you store the array inside curly braces the contents of the array will be the ones you say it to be

Answer 2

Actual strings have an enclosing NULL character (\0), so that's why the first one it's bigger. The second is just an array of characters

Answer 3

because it contains 8 characters

Answer 4

Bebida Roja, so when we store string in array during declaration time with every character in single quote the string does not contain any null character? Please just confirm this, I will be happy then .

Answer 5

Airee you mean the second one has no null character in last ??

Answer 6

yes, any string within double quotes will contain a null terminating character, thats why the first one has size 10, but your question was about the second string.

Answer 7

Babida Roja, Thanks man