#include <iostream> using namespace std; int main() { int a[4]={1,2,3,4}; a[1]=*(a+2); *(a+2)=a[3]++; cout<<a[1]+a[2]; } could someone explain (comment each line) why the output is 7 ?

Answer 1

int a[4]={1,2,3,4}; //Defines a 4 elements array
a[1]=*(a+2); //Assigns the value stored in the third element to the second element of the array. Now a[]={1,3,3,4}.
*(a+2)=a[3]++; //Now assing the value stored in the last element to the third element of the array and after that add one to the last element. Now a[]={1,3,4,5}
cout<<a[1]+a[2]; //Prints the sum of he second and third elements in the array, that is 3+4 which is equal to 7.

Hope it helps...

Answer 2

*(a+2) is simply the element in index 2 of your array ie 3.
therefore a[1]=3.

now a[3] is 4 and its a post increment
hence you are putting that into *(a+2) ie index 3 in the array
now your array looks like {1,3,4,5}. hence a[1]+a[2]=3+4=7

Answer 3

thank you all for clear explanations

Answer 4

both explanations are correct