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SOLVED ◇ Why Passing by Reference in Operator Overloading
I noticed that in the operator overloading function's parameters we pass by reference an other object of the same class. But why is that? why should I pass by reference and not by value.
1 Resposta
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Martin Taylor oh so i guess it has to do with performance?
Costuma ter perguntas como essa?
Aprenda de maneira mais eficiente, de graça:
