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Find the difference between the sum of digits in a number at odd places and sum of digits at even places.

Eg. 7345 i.e.( 7+4) -(3+5) Output : 3 Entered No. Can be maximum of 100 digits . Language: Python (Python is the priority,other languages can also be used) This question was asked in TCS TNQT 2019

6th Aug 2019, 4:45 AM
MOHD TABISH KHAN
MOHD TABISH KHAN - avatar
4 Respostas
+ 5
It would be best if you shared your attempt first by writing it in the Code Playground and posting a link to it here. I'm assuming you are using the popular concept of calling the first number's place 1, i.e. odd, rather than its index position 0, which is even. n = input() or "7345" # Here "positions" begin at 1 rather than index position 0, # so even index positions mean odd positions here. if len(n) > 100: print("Only 100 digits allowed.") quit() sum_even_positions = sum(int(n[i]) for i in range(len(n)) if i % 2) sum_odd_positions = sum(int(n[i]) for i in range(len(n)) if not i % 2) print(sum_odd_positions - sum_even_positions) https://code.sololearn.com/cUBaChEV0ZMR
6th Aug 2019, 6:10 AM
David Ashton
David Ashton - avatar
+ 3
Find my attempt to ur question... https://code.sololearn.com/cHMMw4DzC4cJ/?ref=app Hope this helps...!!!
6th Aug 2019, 6:35 AM
Kuri
Kuri - avatar
+ 1
And what is your question about this? If you need help to write this program, then show your attempt first, and explain where you are stuck.
6th Aug 2019, 6:06 AM
Tibor Santa
Tibor Santa - avatar
0
#Used my own Variables in the code University=input("Enter the number") even_sum=0 odd_sum=0 University_length=len(University) for student in range(University_length): if student %2==0: even_sum+=int(University[student]) else: odd_sum+=int(University[student]) if even_sum>odd_sum: print("The difference of odd and even position digits sum is",even_sum-odd_sum) else: print("The difference of odd and even position digits sum is",odd_sum-even_sum)
1st Sep 2020, 3:58 PM
Choppadandi Siddeshwar
Choppadandi Siddeshwar - avatar