C++ - Pointers strike again

Question

Why with penultimate instruction (p = "XYZWVU") p changes, but s DOESN'T?

#include <iostream>
using namespace std;

int main() {
const char* p = "12345";
const char **q = &p;
*q = "abcde";

cout << *p << endl;

const char* s = ++p;

cout << *s << endl;

p = "XYZWVU";
cout << *++s;
return 0;
}

Answer 1

When you do

const char* s = ++p;

You are declaring a pointer s and pointing it at the second character within string literal "abcde". At this point, yes, p and s both point to the contents of the same string literal.

Doing

p = "XYZWVU";

however, does not alter the string literal pointed to by s. What this does is change what pointer p is pointing to. When you do this, pointer p and s are each pointing at different string literals.