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Return the number of even ints in the given array. Note: the % "mod" operator computes the remainder, e.g. 5 % 2 is 1.
Can someone solve this pls help
3 Respostas
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print((lambda arrayofintstoget = [int(i) for i in input().split()]: len([iloveobfuscation for iloveobfuscation in arrayofintstoget if iloveobfuscation%(int(int(round(abs(-4096)**(1/6),0)**0.5))) == (iloveobfuscation-iloveobfuscation)]))())
Good luck🙃
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Show us your attempt please