Numbers into words

Question

Enter number: 0
Number Entered: zero
How do I do this????!

Answer 1

Go to code section (where you see codes created by other users) and at the top you will find search bar. Type : numbers words, and you will find many different codes that will give you idea how to do it by yourself.

Answer 2

If you only want to support 1 digit as:
Enter number: 1
Numbers Entered: one

Enter number: 5
Numbers Entered: five

Enter number: 11
Numbers Entered: ???

it is very easy. You could use:
a list,
a dictionary
or a railed if-elif statement.

If you want to support multiple digits as:
Enter number: 6
Number Entered: six

Enter Number: 30
Numbers Entered: three zero

Enter Number: 123456789
Numbers Entered: one two three ... nine

Then in addition you would need a loop:
a for loop,
a while loop,
or a recursive function.

The most problematic part would be to make it print:
Enter number: 10
Number Entered: ten

Enter number: 314159
Number Entered: three hundred fourteen thousands hundred fifty nine

You do not need to focus on the last one yet.

Answer 3

I think that it is possible to write all variants of words and matching numbers in two arrays (for example, from 0 to 100) and depending on the entered number output the result. am I wrong? that's not how it works? then function in a loop program and looking for matching numbers and words, then print the desired result.

Answer 4

Not sure if this helps, but it might point you in the right direction:-

numdict = dict(enumerate(['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten'])) #etc

x = int(input('Type in a number:- '))

try:
print(numdict[x])
except KeyError:
print("Error:- Out of range.")

Answer 5

or learn how dictonaries work in python, and use one gigantic one

Answer 6

A program simple enough to do single digits will go like this:
n=int (input ('Enter a digit'))
if a==0:
print ('Entered number:Zero')
if a==1:
print ('Entered number:one')
And so on