Two variables with the same address

Question

I was messing around with the address of operator and it looks like two variables can be stored in the same address, is this true? Here's the code I was fiddling with:

#include <iostream>
using namespace std;

int main()
{
int m = 2, n = 6;
int &x = m;
int &y = n;
m = ++x;
x = ++m;
n = ++y;
y = ++n;
cout << &m << endl << &x << endl; /*outputs:
0x23fe3c
0x23fe3c
*/

return 0;
}

How is this possible? Isn't there only one variable allowed per address?

Answer 1

int &x = m;
here you didn't create a new variable, you just gave another name to variable m. Now you can access the value at the address &m by using m or x.
Same happens in the next line:
int &y= n
One value is stored in memory, and you can access it by using n or y variable names.

m= ++x // x=3,m=3 and another name for m is x, so x=m=3
x=++m // m=x=4

Again... y=n=8

Now you print &m and &x, well yeah, they have the same address... they are not two different variables. It's just one variable with two different names.
These x and y variables are called reference variables.

Answer 2

@voja I didn't know about that, thanks. It makes me wonder how many aliases you can give to a single variable.