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ternary conditional (java) [Solved]
Hey, Why is it printing "5.0"? Isn't it suppose to print "5"? Since I added "(int)" before it? https://code.sololearn.com/cJL9g3CxZO3G/#java Thank you! [Solved] https://code.sololearn.com/copwkZGEja04/#java
15 Respostas
+ 3
Alright, so this is pretty redundant... but it works
https://code.sololearn.com/cuuwxLGx1Zb8/?ref=app
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I'm using a keyboard called "ninja pro" which all the keys are invisible lol
Spelling mistake happens đ
Thanks for your answer đđ
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voja yes but in here both true and false statement have int... what if I used 5.8? It will print "5"
My goal is :
If a = 5.0 the output I want is "5" NOT "5.0"
But
If a = 5.8 the output I want is "5.8"
Using thernary conditions...
Is it even possible? LOL
+ 8
Kit Delano Cat oh thank you
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Kit Delano Cat
So is there is any possible way make it print "5"? In ternary conditional?
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No problem LOL
I'm trying to find it for 4 hrs... Still findingđ
THANK YOU FOR YOUR HELP
+ 6
I tired switching (int) to the false side... Still printing "5.0"
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Mr. đrange It's tried not tired đ. Btw you are comparing double with int so it will be false and return will be 5.0
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Comparing floats and doubles using == operator is not recommended. So kindly read the Oracle documentation once, may be you will get an idea.
+ 3
Yes, if you make second argument int too:
System.out.println((a == (int)a) ? (int)a : (int)a);
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Mr. đrange
This works:
double a = 5.0;
if((int)a - a == 0){
System.out.println((int)a);
}else{
System.out.println(a);
}
+ 2
Mr. đrange yeah, now I get what you want... I guess I am a bit tired.. đ
+ 1
java is that weird.
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double a = 5.0;
System.out.println((a == (int)a) ? String.valueOf((int)a) : a);
Shorter and works fine.
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