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Can anyone trace the pointer execution?
5 Respostas
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Q-32) array[2] points to "h", then +1 gives the output "o".
Q-33) option A is pointing to something that is not in the array.
Always look for the value at or dereferencing operator (*) to see where it is placed in the expression to get the answer right.
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~ swim ~ agreed
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~ swim ~ Q-33) there is some correction in option C I guess, that is written separately.