Please tell me friends the output of this code? Print("% d ",scanf("%d",&i))

Question

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Answer 1

int i;
printf("%d", scanf("%d", &i));

%d in both cases refers to a decimal
scanf will get input from the user. In this case of type int %d.
It uses &i to access the memory address of the variable i so that the input value can be put into it.
It then returns the number of item it successfully filled. In this case 1 or 0.
1 is what is output if successful otherwise 0.

Answer 2

Briefly, this code gets the integer number as i then it writes value of i in the output.

its equal to this code:
int i;
scanf("%d", &i);
printf(%d",i);

Answer 3

@Ehsan Bojnordi

it won't print the value of i. It will print the return value of the scanf method, which will be either 1 if successful or 0.