Reading the value of a pointer from a function

Question

double function (int x,int* pointer){
int address; /*this is the variable I want my pointer value to be saved in*/
pointer=&address;
if(x==0)
*pointer=1;
else
*pointer=0;
return x; /*function does not return a pointer, but something else*/
}

int main(){
int address;
function(0,&address);
printf("%d",address);
}
This code is a part of a larger code, but I'm only having problem with this part, so forgive me if it doesn't make much sense. How do I read the value of a pointer from a function and print it?

Answer 1

mel1705 What is this code from?

I hope it's not from something being built by professional developers. I'd be worried to see the rest of the code base.

Answer 2

Ah... I thought you were fixing someone else's code.

Answer 3

David Carroll no, this is part of my assignment, I am a beginner. And this is just a snippet I made to present a problem, not a real part of the code.