Why as output I had 1 ab and not 1 a?

Question

public class Security {

int x = 2;

public static void main(String[] args) {

int x = 1;
System.out.println(x);
switch(x){

case 1:
System.out.print('a');

case 2:
System.out.print('b');
break;

}
}
}

Answer 1

Hichem GOUIA for x=1 you get "ab" because case 1 is first executed and there is no "break" after printing 'a'.
So the control moves to case 2 and prints 'b'. This is generally called "fall through".

But if you make x=2 then directly case 2 is executed and prints 'b'.

The value passed in switch and the case inside switch has to match.

Answer 2

because after case1 is not break

Answer 3

Aahhhh if I don't put break; between the switch cases so all the cases will be executed
Big thinks for your help👍👍

Answer 4

without breaks, it will execute only all cases after true case

case 0:
System.out.print('@'); //false, not executed
case 1:
System.out.print('a'); //true, first executed
case 2:
System.out.print('b'); //second executed
break;

Answer 5

And if switch the first declaration int x= 1 and the second to int x = 2 I obtain as output
2
b
Instead of
2
ab

Answer 6

Yes but the value of x is changed from 2 to 1!!

Answer 7

In the second declaration is x = 2 then the case 1 is not true. It don't print "a" and goes to case 2

Answer 8

int x declared as local variable in main() is not the same as x declared as Security class property
try this

public class Security {
static int x = 2;

public static void main(String[] args) {
int x = 1;
System.out.println( Security.x );
System.out.println( x );
}}

Answer 9

Thanks for your clarification 😊