Int x=4; x+=(x++)+(++x)+x;System.out.println (x);

Question

the answer will be 20 can any one explain this question

Answer 1

First, you have 4.
Then in the second line you have this:
4 += 4 + 6 + 6
x++ means you put value of x first and then it is incremented, so you got 4. In the case of ++x the value of x is incremented once again, that's why you got 6.

Answer 2

20

Answer 3

++x increments then assigns value, x++ assings value then increments.

Answer 4

21 is coming 😑

Answer 5

The answer here should be 22. Below is the reason which I can see

x+=(x++)+(++x)+x
which is same as x=(x + ((x++)+(++x)+x)
Now with order of prioritty (x++) will be executed first.
x++ will increment the value of x first and return the old value, which is 4

Next ++x will be executed
++x will increment the value first and return the new value, which 6

Now our problem is changes like below
x=6
x=x+4+6+x

Which is 22!

However when I execute x=x + ((x++)+(++x)+x then I am getting 21. I am yet to figure out the reson why removal of bracket changes the execution

Answer 6

Var x = 4
X *= 2
X -=3
X++
Println(x)