Usin arrays write a program that inputs five numbers and if there are any zeros, removes them and shows the app nput without 0s.

Question

My attempt so far

#include <iostream>
using namespace std;

int main()

{
int i = 0;
int num[5];
for (int j = 1; j < 6; j++)
{
cout << "Enter number [" << j << "]= " << endl;
cin >> i;
}
for (int j = 0; j < 5; j++)
{
if (i!='0')
{
i++;
}
}

cout << "Non zero: " << endl;
for (int i= 0; i < 5; i++)
{
cout << num[i] << "\t";
}

return 0;
}

Answer 1

int main(){
int numbers[5];
int counter = 0, i = 0;
for (int j = 0; j < 5; j++)
{
cout << "Enter number [\" << j << \"]= " << endl;
cin >> i;
numbers[j] = i;
}

for(int x = 0;x < 5;x++)
if(numbers[x] != 0)
counter++;

int numbers2[counter]; // declare a second array to the size of non-zero count

for(int x = 0,z = 0; x < 5; x++)
if(numbers[x] != 0){
numbers2[z] = numbers[x];
z++;
}

for(int x = 0; x < counter; x++)
cout << numbere2[x] << ',';

return 0;
}

Answer 2

blackwinter thank you so much. you have no idea how helpful you’ve been.

Answer 3

Thanks. unfortunately it doesn’t. If there was a way that I could keep the first and last for and change the middle for it would be great.

Answer 4

if your looking to actually remove the zeros then, I would use a vector.
http://www.cplusplus.com/reference/vector/vector/
edit:-
On second thoughts.... I would use list:-
http://www.cplusplus.com/reference/list/list/

Answer 5

how can I store non zero elemnts? sorry I’m so new at this.

Answer 6

@blackwinter
your method requires you to declare a seconds "empty" array of the same size as the first..now if you assign all the non-zeros to this second array, all of the other elements will be assigned a default value of....guess what?....zeros.

Answer 7

rodwynnejones do you have any other way to do this?