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Is that considered recursion?
I wrote a code for a password generator function and added a condition in the function such that: If the random password is repeated (generated before): the function returns itself (return func()) I'm new to the recursion concept and that project was a good chance to try it, but I don't actually know if such a condition would be met so that I can check if the code works.
5 Respostas
+ 6
You call your function again from the inside of the function, so formally it's recursive.
However:
The condition you wrote, never seems to be true, so the recursion is never actually kicked off.
Try to run this version:
import string, random
# By: Ali Abdelhady
L = []
# A random password generator
def password(i):
"""
A function that generates a random password
"""
print(i)
a = [i for i in (string.ascii_letters + string.digits + '@#$%^&*?></!~')]
b = ''
max_len = random.randint(9, 16)
for char in range(max_len):
c = random.choice(a)
b += c
if b not in L: # base case
L.append(b)
return b
else:
return password(i+1) # recursion
print('here is a password suggestion:')
for i in range(1000):
print(password(0))
I print out an index, with each recursive call increasing by one, and call the password a thousand times.
But if you look at it, index remains 0 in every case.
+ 7
Hi,
a recursion has the following pattern:
fun recursion(value):
if......
return sth
else
return recursion(anotherValue)
your code is slightly different although it has some elements of recursion.
If you run password() the first time, L is empty and your password is not in L.
the recursive call will never be executed.
Idea: call password() if generated pw is not in the List
(I promise - you get a time out)
One Idea to make it a bit recurslve is to generate exactly 10 Passwords.
Changing your prog a littlebit could lead to that prog:
https://code.sololearn.com/cRZPFpH56k0L/#py
+ 4
Can you show us your code? Let's have a look at it!
+ 1
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HonFu Thank you
So, the condition is not really needed, sometimes I have that habit of trying to make things perfect😅😅