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Int main(){int a; a=31&14+5*sizeof(6.4);printf("%d",a) } output=2 how?????
8 Respostas
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About the single & it is bitwise AND operator. SoloLearn got a good intro on that subject here
https://www.sololearn.com/learn/4070/?ref=app
P.S. You can edit your text bro, no need to post a typo fix as another text reply : )
+ 1
Are you sure the output was 2? I think it's rather 22 though.
* Having known the default type used for floating point literal is double, assume sizeof(double) = 8.
31 & 14 + (5 * sizeof(6.4))
31 & 14 + (5 * 8)
31 & 14 + (40)
31 & (14 + 40)
31 & (54)
Final result: 22
Dec Binary
31 00011111
54 00110110
----------------------- &
22 00010110
I could be wrong though;
+ 1
It could be the book mistake I don't know but I think your explanation is right thnku
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I got 22 for output of the code bro ...
Try to run it in Code Playground, you'll see ...
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Is this type of questions you can expect in your coding test placements
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Didn't you say "the book mistake"?
I don't know about placements, but looks common for a challenge.
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What is single & b/w 31 and 44 means
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14*
Costuma ter perguntas como essa?
Aprenda de maneira mais eficiente, de graça:
