Math logarithm

Question

My problem is idk how to convert it into expression rightly:

Given problem is:
3 lnx divided by 2*y

Answer 1

RCH
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Answer 2

Here are other useful math functiones:

https://docs.python.org/3.1/library/math.html

Answer 3

thankyousomuch! i’ll try it

Answer 4

but idk whats wrong with my code it always result to type error: float object is not callable

Answer 5

#Get the value of c
import math
x = float(input("Kindly enter the value of x:"))
y = float(input("Kindly enter the value of y:"))
z = float(input("Kindly enter the value of z:"))

c = x * (1 + (y / z)) pow(z * x, 1)

print("The value of c is:", c)

test data:
x = 1.2
y=3.5
z = 4..3

Answer 6

c=x*(1+(y/z))*z*x —- this one is directly multiplied not raising to the power of

it should be raised to z(x) how can i do that?

Answer 7

how bout this one it also resulted to float erorr

import math

x = float(input("Kindly enter the data for x:"))
y = float(input("Kindly enter the data for y:"))
z = float(input("Kindly enter the data for z:"))

b = (-y - math.sqrt (abs((pow(y,2)) - 4 * x * z))) / (2 * x + y) + math.log (3 * x (pow(1,4)))

print(b)

Answer 8

equation -y- square root of the absolute value of y^2 -4xz divided by 2x + y then add the value to log 3x raise to 1/4