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How can I find the location of the unique item of more than two lists?

How can I find the location of the unique item of more than two lists? For example: A=[2,3,4,5,6] B=[2,4,5,6,8] C=[3,2] Return B[4] (I am actually making a sudoku solver, and want to use this to locate items)

12th Feb 2020, 5:07 AM
Danny Mientjes
Danny Mientjes  - avatar
6 Respostas
+ 1
add all lists of block9 into addlist. res =list( filter(lambda x: addlist. count(x) ==1,addlist) now find the right list. for l in block 9: if res[0] in block9...
12th Feb 2020, 7:24 AM
Oma Falk
Oma Falk - avatar
12th Feb 2020, 11:36 AM
Oma Falk
Oma Falk - avatar
0
you can always merge the array first
12th Feb 2020, 5:33 AM
Taste
Taste - avatar
0
Thanks Jay, I am not sure if that's going to work. you know, I numbered the sudoku into 81 cells, and made functions to get all the data out of these cells, and row numbers, column numbers, block numbers and overlapping cells. So now I am struggling to go to the next level, filtering out the "hidden singles" (maybe later I want to trace the "naked sets" and "hidden sets" not sure if this is possible for me) But for now I want an easy way to get the singles out of 9 lists (or sets), and get the cell number and location: block: 6 34 ['2', '3', '4', '6', '8'] 35 ['1', '2', '3', '4', '6'] 36 [] 43 ['2', '4', '6', '8', '9'] 44 ['2', '4', '6', '9'] 45 [] 52 ['2', '3', '4', '9'] 53 ['1', '2', '3', '4', '9'] 54 ['1', '2', '3', '9'] block: 7 55 [] 56 [] 57 [] 64 ['6'] 65 [] 66 [] 73 [] 74 ['6', '8'] 75 ['8', '9'] block: 8 58 ['6', '7', '9'] 59 ['6', '7', '9'] 60 ['1', '6', '7'] 67 ['2', '3', '4', '6', '8', '9'] 68 [] 69 ['2', '4', '6'] 76 ['2', '3', '4', '6', '7', '8', '9'] 77 ['2', '4', '6', '7', '8', '9'] 78 ['2', '4', '6', '7'] block: 9 61 ['5', '6', '9'] 62 [] 63 ['6', '9'] 70 ['2', '3', '4', '6', '9'] 71 ['2', '3', '4', '6', '9'] 72 ['2', '3', '6', '9'] 79 [] 80 ['2', '3', '4', '6', '7', '9'] 81 ['2', '3', '6', '9'] so, I want to get: 60 --> '1' 61 --> '5' 75 --> '9' 80 --> '7' or 60 --> [0] 61 --> [0] 75 --> [1] 80 --> [4]
12th Feb 2020, 6:56 AM
Danny Mientjes
Danny Mientjes  - avatar
0
Thanks Oma. But I can't get it working. is this what you mean: addlist=[['5', '6', '9'],[],['6', '9'],['2', '3', '4', '6', '9'],['2', '3', '4', '6', '9'],['2', '3', '6', '9'],[],['2', '3', '4', '6', '7', '9'],['2', '3', '6', '9']] res =list( filter(lambda x: addlist.count(x) ==1,addlist))
12th Feb 2020, 8:31 AM
Danny Mientjes
Danny Mientjes  - avatar
0
Wow, Oma! Thanks that's perfect. With this I can finish my Sudoku project. Thanks you very much
12th Feb 2020, 12:58 PM
Danny Mientjes
Danny Mientjes  - avatar