Whats wrong with this JS code?

Question

Like i can run it offline without internet successfully, but once i run it with the internet, it brings an error.

alert("This checks if you passed a test");

//first i created a Array with the grades.
var grades = ["failed", "credit", "merit", "distinction"]

//next i created a funtion
function testResult(score){
if (score <= "39") {
return grades[0]
} else if (score <= "59"){
return grades[1]
} else if (score <= "79"){
return grades[2]
} else if (score >= "80"){
return grades[3]
}
}
//This where i call it
console.log(testResult("90"))

Answer 1

You can't compare quotes with numbers. In all if statements and in the last line remove the quotes.

Answer 2

The code runs fine from what I can see
90 is distinction and as I changed the value in the console.log line so it changed the array position
https://code.sololearn.com/WGi18LIn6VFH/?ref=app

Answer 3

"90", "39", these are string.

console.log(typeof "90");
console.log(typeof 90);

Use number instead for comparison

https://code.sololearn.com/WYiLQ2ulToL7/?ref=app

Answer 4

Further explanation

it seems to work when comparing string,

Because string are compared lexicographically.

Take for examples,

"b" > "a"

https://code.sololearn.com/Wl0WNT3EJa2b/?ref=app

but because "1" < "9"

so "100" < "99"

so we should still use number for numbers.

Answer 5

What kind of error is it? What does it tell you?

Answer 6

You should use integer in Your condición instead of string and have a range like else if (score >=40 && score <= 59)

Answer 7

problem in strings. 1 !=== “1”