+ 6

If we do as below ,will value of t calculated in function goes to address of t?

function definition: int func(int X,int y,int z,int &t) {t=(X+y+z)/2;}

29th Feb 2020, 8:10 PM
Addaganti Naga Sai Rajeev
Addaganti Naga Sai Rajeev - avatar
2 Respostas
+ 3
Actual argument corresponding to t is gets changed as t value, in c++. Pls Tag language also In c, you need to use pointer instead of variable to store address. [&t => *t]
29th Feb 2020, 8:22 PM
Jayakrishna 🇮🇳
+ 3
You dod not specify a relevant language in thread tags, so In C you would probably use pointer to pass address of variable <t>. int func(int X, int y, int z, int* t) { *t = (X + y + z) / 2; // no return value ??? } In C++ you have the option to use reference. int func(int X, int y, int z, int& t) { t = (X + y + z) / 2; // no return value ??? } I think the way <t> is defined in your example isn't quite right if you meant C language, it is fine in C++. And since the function doesn't return anything, you might want to change its return type to `void`. You are returning the result out through the <t> parameter after all.
29th Feb 2020, 9:31 PM
Ipang