problem solving

Question

there are some problems in solo learn to complete

easy,, but i have some problems
see this problem👇

You write a phrase and include a lot of number characters (0-9), but you decide that for numbers 10 and under you would rather write the word out instead. Can you go in and edit your phrase to write out the name of each number instead of using the numeral?

how i can get strings that sololearn problem automatically give to test my code??.i write my algorithm and works perfect, the problem is how to get the test phrases of solo🙄🤔
pls help me,😤😤😤

Answer 1

Just do it as if you are taking input from the user.
For example in cin(in C++),input()(in python),scanf()(in C)

Answer 2

no, problem is that, user wont enter the phrase,
the sololearn has 6 test case, that they are fix
each test case has one input!!!

Answer 3

Ali Najafian you can consider sololearn as a person who is going to run your program 5 times and input an phrase as input everytime

Answer 4

Is it test case 3 ?

Answer 5

import string

def solve(s):
for ch in s:
if ch == '1':
print("one", end = '')
elif ch == '2':
print("two", end = '')
elif ch =='3':
print("three", end = '')
elif ch == '4':
print('four', end = '')
elif ch == '5':
print('five',end = '')
elif ch == '6':
print( 'six', end = '')
elif ch == '7':
print('seven', end = '')
elif ch == '8':
print('eight', end = '')
elif ch == '9':
print('nine', end = '')
elif ch == '0':
print('zero', end = '')
elif ch == '10':
print('ten', end ='')
else:
print(ch , end='')

s=input()
solve(s)

Answer 6

thnaks, solved!!
but one test case failde!!🤔
and it is locked i can not see result, how i can solve and debuge that, any idea?

Answer 7

yes

Answer 8

It must be because your program is not converting 10 to "ten"

Answer 9

Share your code here

Answer 10

i think problem is 10
my code mistake🤪

Answer 11

ch =='10'
is wrong phrase!🙈😀

Answer 12

Here I have fixed it👇
https://code.sololearn.com/c4VPoOhKN01F/?ref=app

Answer 13

thanks

Answer 14

my code was so bad
what's your idea?

i think i could write it using 2 nested iteration through a dictionary and input steing, and solve that faster,
is it faster or first one?

Answer 15

Continuation:

else if(str.at(i) == '7'){
str.erase(i,1);
str.insert(i,"seven");

}

else if(str.at(i) == '8'){
str.erase(i,1);
str.insert(i,"eight");

}

else if(str[i] == '9'){
str.erase(i,1);
str.insert(i,"nine");

}
}

bool isReplaced = ReplaceString(str,"onezero","ten");

if(isReplaced){
cout<<str;
}
else{
cout<<str;
}

}

bool ReplaceString(string &s, const string &oldSubstr, const string &newSubstr){

bool isReplaced = false;

int currentPosition = 0;

while(currentPosition < s.length()){

int position = s.find(oldSubstr, currentPosition);

if(position == string::npos){
return isReplaced;
}
else{

s.replace(position,oldSubstr.length(),newSubstr);
currentPosition = position + newSubstr.length();
isReplaced = true;
}
}

return isReplaced;

}

Answer 16

yes, i did it, but didn't passed

Answer 17

no idea🙄🙃🤔

Answer 18

Here's my code in Java I used String and StringBuilder class to display the output
Scanner s = new Scanner(System.in);

System.out.print("Input: ");
String strn = s.nextLine();

StringBuilder str = new StringBuilder(strn);

for(int i = 0; i < str.length(); i++){

if(str.charAt(i) == '0'){
str.deleteCharAt(i);
str.insert(i,"zero");
}

else if(str.charAt(i) == '1'){
str.deleteCharAt(i);
str.insert(i,"one");
}

else if(str.charAt(i) == '2'){
str.deleteCharAt(i);
str.insert(i,"two");
}

else if(str.charAt(i) == '3'){
str.deleteCharAt(i);
str.insert(i,"three");
}

else if(str.charAt(i) == '4'){
str.deleteCharAt(i);
str.insert(i,"four");
}

else if(str.charAt(i) == '5'){
str.deleteCharAt(i);
str.insert(i,"five");
}

else if(str.charAt(i) == '6'){
str.deleteCharAt(i);
str.insert(i,"six");
}

Answer 19

Here's the continuation:

else if(str.charAt(i) == '7'){
str.deleteCharAt(i);
str.insert(i,"seven");
}

else if(str.charAt(i) == '8'){
str.deleteCharAt(i);
str.insert(i,"eight");
}

else if(str.charAt(i) == '9'){
str.deleteCharAt(i);
str.insert(i,"nine");
}

}

String st = str.toString();

if(st.contains("onezero")){
System.out.print(st.replaceAll("onezero","ten"));
}

else{
System.out.print(st);
}

Answer 20

Here's my code in C++:

#include <iostream>
#include <string>

using namespace std;

bool ReplaceString(string &s, const string &oldSubstr, const string &newSubstr);

int main(){

cout<<"Input: ";
string str;
getline(cin,str);

for(int i = 0; i < str.length(); i++){

if(str[i] == '0'){
str.erase(i,1);
str.insert(i,"zero");
}
else if(str[i] == '1'){
str.erase(i,1);
str.insert(i,"one");

}
else if(str[i] == '2'){
str.erase(i,1);
str.insert(i,"two");

}
else if(str[i] == '3'){
str.erase(i,1);
str.insert(i,"three");

}

else if(str.at(i) == '4'){
str.erase(i,1);
str.insert(i,"four");

}

else if(str.at(i) == '5'){
str.erase(i,1);
str.insert(i,"five");

}

else if(str.at(i) == '6'){
str.erase(i,1);
str.insert(i,"six");

}