How do you think I could optimize this code in Python?

Question

https://code.sololearn.com/cW2V6MzVnbb5/?ref=app

Answer 1

Jean Carlo Martinez Lo Iacono

cadena = input()
print ("Deja Vu" if any(cadena.count(l)>1 for l in cadena) else "Unique")

Answer 2

You don't need norepetida, because you're doing nothing with it.

So you can shorten the first part like this:

cadena = input()
repetida = 0

for i in cadena:
if cadena.count(i) > 1:
repetida += 1

Another thing you could do is just make repetida a boolean.

Because all you need to know is:

Is one of the letters in there more than once or not?

Then your code looks like this:

cadena = input()
repetida = False

for i in cadena:
if cadena.count(i) > 1:
repetida = True

if repetida:
print ("Deja Vu")
else:
print ("Unique")

Using the extended for loop of Python, you can shrink this further. Actually let's get rid of all variables:

for i in input() :
if cadena.count(i) > 1:
print ("Deja Vu")
break
else:
print ("Unique")

Python has a nice function any which can get rid of the loop.

cadena = input()
if any(cadena.count(l)>1 for l in cadena):
print ("Deja Vu")
else:
print ("Unique")

Answer 3

excellent I will take it into account, thanks