Need to determine the number of pozitive numbers until the first negative number

Question

When testing this program, I usually use the values to be in this order: 1, 2, 3, 4, -5, 6, 7, 8.
If I use only one negative number when executing the program, it does what I want to, but if I use more negative numbers, for example the order: 1, 2, -3, 4, -5, 6, 7, -8; It will show multiple times "s =...", which I don't want to. I tried using the while loop for this, but I couldn't get it to work. Any help is appreciated.

This is my code

#include <iostream>
using namespace std;
int main()
{
int i, j, k, s=0;
int arr[2][2][2];
for(i=0;i<2;i++)
{
for(j=0;j<2;j++)
{
for(k=0;k<2;k++)
{
cout<<"Value on ["<<i<<"]["<<j<<"]["<<k<<"] ";
cin>>arr[i][j][k];
}
}
}
for(i=0;i<2;i++)
{
for(j=0;j<2;j++)
{
for(k=0;k<2;k++)
{
if(arr[i][j][k]>=0)
{
s=s+1;
}
else
{
cout<<"s = "<<s;
}
}
}
}
return 0;
}

Answer 1

You could simply add a
return 0;
after printing 's', that way the program ends after the first negative number has been found.
Otherwise a boolean flag can help you to control the loop.