Jungle camping -- how do I count input from the string

Question

sounds = input()

total = 0
gcount = sounds.count('Grr')
rcount = sounds.count('Rawr')
scount = sounds.count('Ssss')
ccount = sounds.count('Chirp')

total = gcount+rcount+scount+ccount

for i in range(total):

if (sounds == 'Grr'):
total = total + 1
print('Lion'+" "*total)

elif (sounds == 'Rawr'):
print('Tiger'+" ")

elif (sounds =='Ssss'):
print('Snake'+" ")

elif(sounds =='Chirp'):
print('Bird'+" ")

# the issue here is that I'd typically request number
#of sounds by soundnum= int(input()), and
#multiplying that by sounds. Code coach has made
#it clear it wants only sounds as input then the
#according output. Any suggestions?

Answer 1

Thank you maf

Answer 2

👑 Shewe Uchi K 👑 If there is a string such as
words = "Hello how are you"
How to count how many words are there?
You can use words.split(" ") to tell python that " " or spaces between words makes them separate so now there are 4 words, separated into a list.

sound = input().split(" ")
a = []

for i in sound:
if i == "Rawr":
a.append("Tiger")
elif i == "Chirp":
a.append("Bird")
elif i == "Ssss":
a.append("Snake")
else:
a.append("Lion")

print(' '.join(a))

I created a new list, and appended/added an animal into it according to its sound.

Answer 3

👑 Shewe Uchi K 👑 :) np