What is the happening in this case?

Question

int x=3;
while(x++<10)
{
x+=2;
}
cout<< x;
After completing the 2nd loop the value of 'x' becomes 9, and when it checks for the condition for the 3rd loop i.e. 9++<10 meaning 10<10
Shouldn't that be false?
But that's considered to be true by compiler.
Even if I put the condition like while(x++<=10)
It is showing the same output

Answer 1

Purvank Bhiwgade
Initially the value of x is 3.
When the loop executes -
while (x++ < 10)

First it checks (3 < 10), the condition is true.
Since here ++ is post increment operator (x++) that's why it performs operations in following way -
1 - checks condition
2 - Increment value
3 - Then enters in loop

So after this (x++ < 10) means-
(3 < 10) condition is true and value of x is incremented by 1 so it becomes 4 , then it enters in loop
x += 2;
value of x = (4 + 2)becomes 6.

Agai it checks the condition
while(x++ < 10) , here value of x is 6.
The condition is true (6 < 10)
And then value is incremented by 1,
So x becomes 7, then
It enters in loop and execute x += 2;
And value of x = (7 + 2)becomes 9.

Again it checks condition (9 < 10), the condition is true , then the value of x becomes 10
and again it enters in loop x = (10+2)
at last value of x becomes 12.

Answer 2

X++ is post increment, meaning it will evaluate the value, then increment it , then it will finally store it.