How to find a leap year in Python??

Question

#My Code

def Calendar (year):
if n/int(4):
print ("True")
elif n/int(100):
print ("False")
elif n/int(400):
print ("True")

n = int(input("Enter the year:"))
Calendar (n)

"QUESTION: To find a leap year.. The year can be evenly divisible by 4 is leap year.. The year can be evenly divisible by 100 is Not a leap year.. The year is also evenly divisible by 400 is a leap year..

Note: The output should in Boolean True or False.. If it is leap year it should print True else False "

Answer 1

https://code.sololearn.com/c795F0UI7R6W/?ref=app

Hope it helps!!

Answer 2

Thanks bro.. It's helped.