Explain it plzzz

Question

#include <stdio.h>

int main() {
int x=0,y=0;
if(x++&&y++)
printf("x=%d y=%d",x,y);
else
printf("y=%d x=%d",y,x);
return 0;
}

Answer 1

Here x++ is 0 which is false so it will not check second condition.

So y = 0 because didn't check next condition.

x = 1 because x is incremented by 1 after doing operation.

Answer 2

in C, any number which is null has the boolean value 'False', else, it's 'True'.
but x++ and y++ are postfix incrementation, so x and y will be tested first, before incrementing.
to test if 'a and b' is true,
if a is false, no need to test b, a and b is automatically false,

if a is true, then a and b has the value of b

in our case a=x++=0 which is false, (but after the test, x is incremented to 1)
so no need to test y++ anymore. the if condition is not satisfied and it jumps to the esle statement where 'y=0 x=1' is printed

https://www.sololearn.com/learn/C/2917/