Python list

Question

How can I create a function that return the smallest number that is divisible by 3 from a list.
Input [‘2’, ‘1’, ‘3’, ‘4’, ‘6’]
Output = 3

Answer 1

You could use list comprehension
b=[i for i in list if int(i)%3==0]
print(min(b))

Answer 2

Here is the instructions you should follow :

1) Filter the elements of the list so that it only contains the elements which are divisible by 3!

2) Return the smallest number from the list.