Y iam not getting address of the variable in printf("\n%u",a); where a is declared as int ..

Answer 1

Use &a

Answer 2

Using %u to print addresses is undefined behavior.

You must use %p specifier for addresses and cast to a void pointer (this is required by C99):
printf("%p\n", (void *)&a);

you can read more about it here:
https://stackoverflow.com/questions/9053658/correct-format-specifier-to-print-pointer-or-address

Answer 3

Then I will get the value of a..

Answer 4

a returns value..
&a returns address..
printf("%u", &a) ;

Answer 5

Ooops..a u r right..thanks to remember me I forget that

Answer 6

S ..thanks mr.Avinesh and to mr.JayaKrishna