Have anyone solved the "No Numeral" problem in python?

Question

Except the test case 3, all other test cases are passed. I can't figure out the problem.

sen = input()
senti = []
for n in sen:
if n == "0":
senti.append("no")
elif n == "1":
senti.append("one")
elif n == "2":
senti.append("two")
elif n == "3":
senti.append("three")
elif n == "4":
senti.append("four")
elif n == "5":
senti.append("five")
elif n == "6":
senti.append("six")
elif n == "7":
senti.append("seven")
elif n == "8":
senti.append("eight")
elif n == "9":
senti.append("nine")
elif n == "10":
senti.append("ten")
else:
senti.append(n)

for i in senti:
print(i,end="")

Answer 1

Post your code so that we can see

Answer 2

I've inserted the code

Answer 3

Yes why not many and many of peoples have solved it . Show us your try so that we can help you.

Answer 4

Write 10 case before 1.
Otherwise it is read as 1 and 0..
Edit:
And also 10 is not char.. It's a string so use split method.. By that approach, order is not a matter also..

Answer 5

case 0 print zero