Why this method don't right?

Question

# x.remove(obj)

x = [1, 2, 6.06, 9]
print(x.remove(1))

How to write, help please?

Answer 1

x = [1, 2, 6.06, 9]
x.remove(1)
print(x)
# "remove" returns "None" so "None is printed (in your code)..

Answer 2

a=[1,2,3,4]
a.reverse()
print(a)

Answer 3

Blokhin Roman
remove method doesn't return the removed element but pop() method do so when index number passed to it otherwise it will pop last element of list

print (x.pop(0))