const char* equals char[]

Question

Hi all, does anyone know where to put the "\0" to make const char* equal to char[]? If I run this code, one() returns 1 and zero() returns 0, which is kinda strange to me, but I think the "\0" should be able to fix that up somehow. Please let me know!

#include <stdio.h>

char one(), zero();

int main() {
printf("One: %c\n", one());
printf("Zero: %c", zero());
}

char one(){ //Outputs 1
unsigned long long int a = 0.0f;
const char b = .0;
return a == b ? '1' : '0';
}

char zero(){ //Outputs 0
const char* p = "sololearn";
char q[] = "sololearn";
return q == p ? '1' : '0';
}
https://code.sololearn.com/coPR0HmE5czM/?ref=app

Answer 1

That's not the cause of the problem here, it's that you can't compare strings with ==. Have a look at the strcmp function in string.h: http://www.cplusplus.com/reference/cstring/strcmp/

EDIT: with == you are comparing the pointers. The pointers point to different memory locations hence they aren't equal.

Answer 2

Thank you Schindlabua, I forgot to dereference the q and the p, *q == *p returns 1.

Answer 3

Orville Vroemen Careful though, that will only compare the first character!