Parsing string integer value to normal integer?

Question

How to parse a string integer to a normal integer?

eg: string str="ahd14sjd";
int a;
for(int I=0;I<str.length();I++)
{
if(str[I]=='1')
a=str[I];
}
cout<<a;

In above example, The value of 'a' will be ASCII value of 1. but I want to assign 'a' as 1 and print 'a' as 1. how can I do that? (I.e) parsing string integer to a integer?

I hope you understood my question.

Answer 1

string str="ahd14sjd";
int a=0;
int c=1;
for(int i=str.length();i>=0;i--){
if(str[i]>='0'&&str[i]<='9'){
a += (str[i]-'0')*c;
c *= 10;
}
}
cout << a;

Answer 2

The ascii value of 'a' is 97 as an int. If you're trying to get the Integer value of a character, all you need to do is cast the char to an int.

int('a')