Python's 'OR'. HELP

Question

if x == '1' or '2':
print('Success')
else:
print('Unfortune')
_________
x = '1'
> Success
x = '2'
> Unfortune

________

WHY?
HOW TO MAKE IT RIGHT?

Answer 1

What you did here is actually:
if x == ('1' or '2')

so Python first evaluates ('1' or '2') which is '1' and only then it compares x to it

The condition should go:
if x=='1' or x=='2':
blabla

Answer 2

if x == '1' :
print('Success')
elif x == '2':
print('Unfortune')

You have two (or if you will have more) different conditions you must use "elif" keyword in "if-else" operator or keyword "else", if you don't need handle other possible conditions.

Answer 3

Thank you so much!