Consider following 2 codes inside main function.👇👇👇 why output is different in both the cases????

Question

char arr[50],ch;
scanf("%s",arr);
scanf ("%c",&ch);
printf("%s %c",arr,ch);

or

char arr[50],ch;
scanf("%s %c",arr,&ch);
printf("%s %c",arr,ch);

Output of 1st is = arr
Output of 2nd is=arr ch

Answer 1

char arr[50],ch;
scanf("%s",arr);
scanf ("%c",&ch);
//here the remaining \n new line character is assigned to ch.

How to avoid this:
char arr[50],ch;
scanf("%s\n",arr);
scanf ("%c",&ch);

That should be equivalent to your second code.

Answer 2

This is one of the many problems with scanf(). You should avoid the scanf() functions whenever you can, and use fgets() and getchar() instead.

Answer 3

due to white space in the buffer memory.
Second scanf scans the white space and prints the whitespace.

char arr[50],ch;
scanf("%s",arr);
scanf(" %c",&ch);
printf("%s %c",arr,ch);

Will work like second one

because space before %c will skip the white space in buffer memory

Answer 4

Kevin ★ /[inactive]??/ thanks bro...

Answer 5

Sameer Crestha please see again que.. and then Kevin's answer......