When we give solution to a coding problem , why 1 out of 13 case fails ?

Question

Why do the single test case not work with same piece of code rest are working?
Here is password validator program link
https://www.sololearn.com/coach/76?ref=app
Which according to me is perfectly fine
But it is not working for test case 8?
Can anyone please let me know why?

Answer 1

The link you provided leads to the code coach itself.

Answer 2

Prince Yadav, just store your attempt in a code in Playground and link it here, then we'll take a look at the problem.

Or you copypaste it here, since they're generally short.

Lynx, giving him *your* solution will not help him understand *his* mistake.

Answer 3

Ok sorry for it

Answer 4

Your result comes out as strong even if you have less than 2 of the symbols in it.

Answer 5

Doesn't isa(n) always return True ?

Answer 6

Lynx no it returns 1 when the character match with 7 special characters

Answer 7

'if x or y or z' doesn't mean what you think it means.

It means:

if x is truthy or y is truthy or z is truthy.

Every string that's not empty ('') is truthy, so that function indeed always returns 1.

You probably want to find out if n is one of the symbols.

One pattern you can use:

if n in (x, y, z):
...

Answer 8

Prince Yadav line 27. Just add "or x<2"

Answer 9

#password validator
a=input()
def isd(n):
if ord(n)<58 and ord(n)>47:
return 1
return 0
def isa(n):
if '!' or '&' or '*' or '#' or '#x27; or '%' or '@':
return 1
return 0
def lv(a):
b=len(a)
if b>=7:
return 1
return 0
def pv(a):
if not lv(a) :
return 0
z=0
x=0
for i in a:
if i==' ':
return 0
if isd(i):
z+=1
if isa(i):
x+=1
if z<2:
return 0
return 1
if pv(a):
print ('Strong')

else :
print ('Weak')

Answer 10

HonFu
As you suggested, I made a change in my code
Link: https://code.sololearn.com/cb8GAiZf7k6N/?ref=app
Still it is failing in test case 8

Answer 11

I think the error is not inside special character validator fxn
It's somewhere else
Please help me

Answer 12

Prince Yadav you still have to check if there more than 2 special chars.

Answer 13

Thanks to all
Now it is working

Answer 14

This is an approach
import re

def password_validation(password):

numbers = re.findall(r'[0-9]', password)
specialChars = re.findall(r'\W', password)

if len(password) > 6 and len(numbers) > 1 and len(specialChars) > 1:
return 'Strong'

return 'Weak'

print(password_validation(input()))

Answer 15

https://code.sololearn.com/c4DyMG8nQvA7/?ref=app