Hi guys.... What am I missing on my code.i want to return 1 if all the numbers are divisible by two and return 0 if not all

Question

public class Program
{
public static void main(String[] args) {

int div=1;
int nodiv=0;

int [] arr={2,6,8};

for (int i=0;i<arr.length;i++ ){

if (arr[i]/2) {

return div ;

else if (arr[i]!/2);

return nodiv;
}
}
}
}

Answer 1

you have to use modulo% to check if the reminder of the division by 2 is 0 (even number) or not (oddnumber)

if (arr[i]%2==0){
return div;
}
else{
return nodiv;
}

Answer 2

instead of returning, store the result of every for iteration in an array
String [] results ={0,0,0};
for (int x=0; x<arr.length;x++){
if(arr[i]%2==0){
results[x] = "no div";
}else{
results[x] ="nodiv";
}
output the content of the array after the for loop

Answer 3

you are performing a return on the first check reguardless of the outcome. KO

what you want to do is return 0 when one doesn't match or get to the end and return 1 when the loop has ended.

int div=1;

int [] arr={2,6,8};

for (int i=0;i<arr.length;i++ ){

if (arr[i]!/2){
div=0;
break;
}
}

return div;

it would also be better to use 1 variable and just set it to 0 it the divide fails and simply return it at the end again

Answer 4

if (arr[i]!/2) is wrong

if (arr[i]%2 >0) is what you need

Answer 5

first thing I am noticing is:
you are putting if , else if block in one {}, either put in different {} or dont put

Answer 6

public class Program
{
public static void main(String[] args) {

int div=1;

int [] arr={2,6,8};

for (int i=0;i<arr.length;i++ ){

if (arr[i]!/2) {

div=0 ;
break ;
}
}

return div;

}
}
}
OK tried this one Arron... not running and I've tried yours seamiki not running as well

Answer 7

c# code looks like

public class Program
{
static bool DivisibilityChecking(int[] arrr)
{
for (int i = 0; i < arrr.Length; i++)
{

if (arrr[i] % 2 == 0)
{
return true;
break;
}
}

return false;
}
static void Main(string[] args)
{

int[] arr = { 9, 15, 2 };

Console.WriteLine(DivisibilityChecking(arr));
}
}
}