How can I output numbers that evenly divide to the all the positive numbers up until the user's input number?

Question

The user inputs a positive number.
Then the computer outputs all the numbers less than or equal to the user's input number.
Below each number, the computer outputs numbers that evenly divide to that number.

I want the computer to output the numbers that have no remainders.
For example, if the input is 15, the output would be:
15->
1, 3, 5.
But, it will also do the same for every positve number before 15.
Ex:
1->
1
2->
1 2
3->
1 3
.....
15->
1 3 5 15

Answer 1

for(int i=1;i<input;i++) {
if(input%i==0) {
cout<<i<<endl;
for(int j=1;j<i;j++) {
if(i%j==0) {
cout<<j<<endl;
}}}}

//edit:
sorry, that'll output the divisors of the divisors of the input ^^

Answer 2

//evaluate all numbers until half the input
for (int i=1; i<=input/2;i++){
if (input%i==0){//print only the divisors
cout<<i<<endl;
}
}