Ruby - Playing with lambdas

Question

What does this code do?

def say(*args)
args[0].call
end
def something
if block_given?
return yield
end
lambda {puts "Hi."}
end
say something{
lambda{puts "Bye."}
}

Answer 1

As I understand it, something() checks if a code block is given as a parameter to the function. If so, it yields it.
Now, as say method is defined, it calls its first argument. Since it's something and it *has* the block given, it yields it. The block happens to be a lambda function which puts "Bye."

So "Bye." is being put.