C++ cout

Question

Can i output arguments with "cout" in this way:

cout << a,b;

When i write so, then the compiler writes only argument a. It works like this:

cout << a << b;

but i want to know why i cant use the first variant.
(Sorry for my bad english)

Answer 1

Thats why you cant.

See how i made grammatical errors. It basically the same thing. You need to write the correct syntax