JavaScript: Using recursion to create countup

Question

https://code.sololearn.com/WnLSAX5PKls7/?ref=app

How this code returns [1,2,3,4,5] as output?

I analyzed this function as follows,
Since n=5;
const countArray=countup(5-1);
countArray.push(5)
return countArray; // [5]
n=4,
const countArray=countup(4-1);
countArray.push(4)
return countArray; // [5,4,]
n=3,
const countArray=countup(3-1);
countArray.push(3)
return countArray; // [5,4,3]
n=2,
const countArray=countup(2-1);
countArray.push(2)
return countArray; // [5,4,3,2]
n=1,
const countArray=countup(1-1);
countArray.push(1)
return countArray; // [5,4,3,2,1]
Where I went wrong here, How to analyze this code correctly ?

Answer 1

when constArray=countup(5-1)
it doesnt continue to countArray.push immediately
instead it goes into the countup function, so countup(4-1) will run.

here is the process
n=5
constArray=countup(5-1)
n=4
constArray=countup(4-1)
n=3
constArray=countup(3-1)
n=2
constArray=countup(2-1)
n=1
return []
countArray.push(1)
return countArray
countArray.push(2)
return countArray
countArray.push(3)
return countArray
countArray.push(4)
return countArray
countArray.push(5)
return countArray

Answer 2

Taste Thanks a lot .Clear answer

Answer 3

I hate JavaScript