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Question

Hi guys, this code converts the numbers inside the text to words, but a problem occurs with number 10 at the end of the string!
This is more interesting that if we change the first number of the string (1), to 10, the problem will be solved!
Can someone explain that?!

import re
str1 = "1 plus 2 plus 3 p 4 p 5 p 6 p 7 p 8 p 9 p 10"

nums = {"1": "one", "2": "two", "3": "three", "4": "four", "5": " five", "6": "six", "7": "seven", "8": "eight", "9": "nine", "10": "ten"}

d = re.findall('\d+', str1 )
t = tuple(d)

def rep(x, t):
l = len(t)
i = 0
for i in range(0, l + 2):
if i == l:
return x
elif i < l:
if t[i] in x:
x = x.replace(t[i], nums[t[i]])
i += 1
print(rep(str1, t))

Answer 1

Mohammad Moharrami

Problem is that you used replace which will replace all 1's with "one" so next time 10 will not come in String because it already replaced by one like one0.

For example:

str1.replace(1, "one") Here all 1's will be replace by one so on next iteration 10 will not come.

Answer 2

so why in this code everything is ok?

import re
str1 = "10 plus 2 plus 3 p 4 p 5 p 6 p 7 p 8 p 9 p 10"

nums = {"1": "one", "2": "two", "3": "three", "4": "four", "5": " five", "6": "six", "7": "seven", "8": "eight", "9": "nine", "10": "ten"}

d = re.findall('\d+', str1 )
t = tuple(d)

def rep(x, t):
l = len(t)
i = 0
for i in range(0, l + 2):
if i == l:
return x
elif i < l:
if t[i] in x:
x = x.replace(t[i], nums[t[i]])
i += 1
print(rep(str1, t))

Answer 3

Anyway I solved the problem, thanks Anant 🙏🏻