Why is there an error for z

Question

https://code.sololearn.com/cojJbm47nIO6/?ref=app

Answer 1

Oma Falk In theory, you would want to say globals = locals, rather than the other way around as you want to change the globals dict.

You can use globals().update(locals()) instead though.

Answer 2

z is created in the function, so it is not accessible in the scope of main program. To avoid this, create z at the place where x and y are created, or use global.

x=8
y=10
def myadd():
global z
z=44
return x+y
print(myadd())

print(z)

Answer 3

Oma Falk Well I've never been called that before! Yeah, the normal way of doing things is to say global z as other have pointed out.

Answer 4

Russ you are a woman whisperer!
That's it.
(Although I would not survive the day on which I deliver this kind of code to my chief)

Answer 5

i hoped, locals=globals
will do it.