Please help

Question

A = [1, 2, 3, 4, 1]
for i in A:
A[i] = 0
print (A)

Why this code output [0, 0, 3, 0, 1]
Please answer me. I stuck in it.

Answer 1

(RUN THIS CODE TO GET AN IDEA)
A = [1, 2, 3, 4, 1]
print(A,end='\n\n')
for i in A:
print("Original value at index", i,":",A[i])
A[i] = 0
print("After A[i] = 0 gets executed, the value at index", i,"becomes",A[i])
print(A,end='\n\n')
print (A)

Take my advise please revisit your python lesson especially the lesson on array and how indexing works.

Answer 2

When i run the code i get a result of:

[0, 0, 3, 0, 1]

Answer 3

1. i = 1, A[1] = 0, A = [1, 0, 3, 4, 1]
2. i = 2, A[2] = 0, A = [1, 0, 0, 4, 1]
3. i = 0, A[0] = 0, A = [0, 0, 0, 4, 1]
4. i = 4, A[4] = 0, A = [0, 0, 0, 0, 1]
5. i = 1, A[1] = 0, A = [0, 0, 0, 0, 1]

Answer 4

Lothar I also get [0,0,3,0,1]
Ali Abdelhady I think you have made a mistake in 2nd line. In 2nd line i will search for the second value in the list, which is 0. Because in first line the second value was changed into 0 from 2. So it should be
2.i = 0,A[0] = 0, A = [0,0,3,4,1]

Though I am confused because your answer actually match with the answer that was given by Allamprabhu Hiremath in the question.