Width format conversion

Question

In the following code..the output should be: "New price is 8.50" but the decimal part in the number (8.50) which is (8) should be having 4 digits reserved for it..but it doesn't and I really don't understand it...can anyone please explain this to me ?
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#include <stdio.h>

int main() {
float price = 6.50;
int increase = 2;
float new_price;

new_price = price + increase;
printf("New price is %4.2f", new_price);
/* Output: New price is 8.50 */

return 0;
}

Answer 1

/*Width format conversion

In the following code..the output should be: "New price is 8.50" but the decimal part in the number (8.50) which is (8) should be having 4 digits reserved for it..but it doesn't and I really don't understand it...can anyone please explain this to me ?
------------------------------------*/
#include <stdio.h>

int main() {
float price = 6.50;
int increase = 2;
float new_price;

new_price = price + increase;
printf("%06.2f", new_price); // with 0 as fillers
/* Output: New price is 8.50 */

printf("\n") ;
printf("%6.2f", new_price); // with Space as fillers

return 0;
}

Answer 2

Run the above the code and see the difference

(The width field is for the entire converted string not just the whole number part).

Answer 3

Mohamed Taha Yes!

Answer 4

@RKK
Run the above the code and see the difference

(The width field is for the entire converted string not just the whole number part).

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So this means the decimal point is also counted in the 6 reserved digits ?