Explain the output of this program.

Question

#include<stdio.h>
int main()
{
int n = printf("0");
printf("%d",n);
}

The output of this program is =01

EXAPLAIN HOW ?

Answer 1

See this example you will understood much better

https://code.sololearn.com/ckQ5cwZvwzNo/?ref=app

Answer 2

Riya Kumari welcome mam

Answer 3

First printf will print 0 then in second printf u write %d to it will count total characters in first printf and total char is one right so it print 1.
But if u will write like this

Explain the output of this program.

#include<stdio.h>
int main()
{
int n = printf("riya");
printf("%d",n);
}
Then first printf will print riya then it will count total char and total chars are 4 so output will be riya4 hope u understood.

Answer 4

0 -> del printf
1-> números de caracteres del printf(uno caractere)

Answer 5

Gabriel Caldeira Bicalho thnx

Answer 6

Riya Kumari wcm

Answer 7

The output of the program is "01".if we were given the control string in printf as the variable declarations, we simply have to count the number of elements in the string, and that assigns to the variable..

Answer 8

codemonkey thanx

Answer 9

Martin Taylor thx

Answer 10

🐉🐉 thankx alot for the explanation