Can someone SOLVE THIS!

Question

else if(balls[0].color == "red" && balls[1].color == "red" && balls[2].color == "red" && balls[3].color == "red" && balls[4].color == "red" && balls[5].color == "red" && balls[6].color == "red" && balls[7].color == "red" && balls[8].color == "red" && balls[9].color == "red" && balls[10].color == "red" && balls[11].color == "red" && balls[12].color == "red" && balls[13].color == "red" && balls[14].color == "red"... etc

Can someone simplify the conditional, if value in property in an object are whether blue or red (true). Im using this method but still struggling on it

//method
function Color(color){
this.color = color
}

let colors = []
for(var j = 0; j < ballNum; j++){
let color = "yellow"

colors.push(new Color(color))
colorObj = colors[j]
}

var allBlue = Object.keys(colorObj).every(function(k){ if(colorObj[k] === "blue" ){
console.log("blue win")
}
if(colorObj[k] === "red"){
console.log("red win")
}});

https://code.sololearn.com/WvDDRkLGPRV9/?ref=app

Answer 1

balls.every((ball) => ball.color === "red"

https://code.sololearn.com/W8F22YAZ3TOT/#js

btw- My initial reply is a direct quote from mdn.

Answer 2

I would like to give u 1 million likes just to solve this thank u so much for solving the problem! I will insert your name in the game!

Answer 3

"The every() method tests whether all elements in the array pass the test implemented by the provided function. It returns a Boolean value."
source: https://developer.mozilla.org/

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/every

Answer 4

You answering pretty well but i dont know how to implement, can u give an ex?

Answer 5

You're welcome, I'm glad I could help.👍

Answer 6

You should use
var allBlue=arrayName.every(function(k){return k=='blue'});

if(allBlue)
console.log('blue');
else
console.log('as you wish');

Answer 7

Thanks carlo, you both do a great job. Its now working and ill be die in peace