Finding second smallest number out of 3 unknown numbers in c++

Question

my code- (please explain where am i wrong)
#include<iostream>
using namespace std;

int main()
{
int a,b,c;
cin>>a>>b>>c;

if(a<=b && b<=c && a<=c)
cout<<b;

else if (b<=c && c<=a)
cout<<c;

else
cout<<a;
return 0;
}

Answer 1

float n1, n2, n3;

cout << "Enter three numbers: ";
cin >> n1 >> n2 >> n3;

if(n1 >= n2 && n1 >= n3)
{
cout << "Largest number: " << n1;
}

if(n2 >= n1 && n2 >= n3)
{
cout << "Largest number: " << n2;
}

if(n3 >= n1 && n3 >= n2) {
cout << "Largest number: " << n3;
}

Answer 2

Bartas Dausynas U can use equality operator for this situation

yes it should be print two number but u can use exception handling in this case

Answer 3

If you add a small if before the first if.

Like
if(c<a) {
int tmp = c;
c = a;
a = tmp;
}

The problem you have that if c is smaller than a you first if dosnt worl correctly

Answer 4

Navneet Chauhan think,
if (c<=b && b<=a)
what should be the answer?🤔🤔

Answer 5

For kth smallest using std::priority_queue
https://code.sololearn.com/cXtA80Pq8xXK/#cpp

For smallest using std::min_element
https://code.sololearn.com/cVljOO5Y38lC/#