What is the output and why??

Question

int x = 0;
int &y = x; y = 5;
while(x <= 5) { cout << y++;
x++;
}
cout << x;

Answer 1

Variable <y> is an int reference, points to variable <x>. A reference acts like an alias for something it refers to, so in this case <y> is like an alias for <x>. When <x> is modified, the changes also reflects in <y>, vice versa.

* About reference type:
https://techdifferences.com/difference-between-pointer-and-reference-2.html

So when you modify <y>

y = 5;

<x> value also changes to become 5.

Next, a while-loop is setup to go while <x> is less than or equal to 5. The condition satisfies, so the loop begins ...

Inside the loop body <y> value is printed then incrented, and <x> value is incremented.

cout << y++;
Here value of <y> is printed (5) and then incremented to become 6.

x++;
Here value of <x> (6) is incremented to become 7.

NOTE: Remember that <y> is a reference to <x>, so when <y> is incremented, <x> also gets incremented. Also when <x> is incremented, <y> also gets incremented.

Answer 2

First you have to understood the concepts of reference variable how this is working .
For example i write
Int x=5;
Int x=&y ;
If i will increment the value of 5 then y will also increment . Here y is reference of x . If u will change x then y will automatically change if i will add 2 in x means x=x+2, 5+2 so x will be 7 then y also will be 7.
In this program
What is the output and why??
int x = 0;
int &y = x; y = 5;
while(x <= 5) { cout << y++;
x++;
}
cout << x;
here y is reference of x here y is 5 means x is automatically 5 after that in while statement
while(5<=5) which is true after that cout<<y ; here value of y will be print which is 5 after that post increment will increase then value of y so after printing 5 it will increase by 1 so i will be 6 . If y is 6 then x will be also 6 beocz of reference. After that we incrementing value of x++ here x will increase but what was the value of x it was 6 so x++ means x will be 7.If x is 7 so loop will check condition while(7<=5)

Answer 3

Here condition will be false so it will throughout from loop so next cout will print value of x
cout<<x ; and x was 7 so complete Output is
57.

...........Thankyou...........

Answer 4

Do you want the output or an explanation of the output? if you want the output then go to Code Playground to check it.

Answer 5

I want to know why??